Thursday, July 12, 2012

Subnetting Network


Mari belajar subnetting part 1 (berdasarkan jumlah network yang dibutuhkan)
192.5.20.0 => 50 network

50 =>
25
24
23
22
21
20
32
16
8
4
2
1
1
1
0
0
1
0

Jadi 110010 (6 bit)
Gampangnya bilangan terdekat dgn 50 yaitu 32 (6bit)
128
64
32
16
8
4
2
1

0
0
0
0
0
0
0
0

1
1
1
1
1
1
0
0
252
/30

Nilai 256 – 252 = 4 (interval tiap network 4host )
192.5.20.0-192.5.20.3
192.5.20.4-192.5.20.7
Dst….
Subnet 192.5.20.0
Valid Host 192.5.20.1-192.5.20.2
Broadcast  192.5.20.3
·         Max Subnet 26 = 64
·         Max Host (22 – 2) = 2
Sekian

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